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cos(x+π),cos(π-x)

求曲线y=cos x(0 x π)的垂直于直线√2x-y=1的切线方程
求曲线y=cos x(0 x π)的垂直于直线√2x-y=1的切线方程用五点法画出函数y=-cos(x π/3) 1的图像
用五点法画出函数y=-cos(x π/3) 1的图像y=cos(x π/3)的函数简图
y=cos(x π/3)的函数简图已知函数f(x)=sin(x-[π/3]) 3cos(x-[π/3]).
已知函数f(x)=sin(x-[π/3]) 3cos(x-[π/3]).y=cosxcos(x π/6)的最小正周期
y=cosxcos(x π/6)的最小正周期
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